python3解释器对列表[1,2,[3,4],5,6]使用reverse方法执行的结果为()。A[6,5,[3,4],2,1]B[6,5,[4,3],2,1]C[6,5,2,1,[3,4]]D报错
a=[9,6,4,5]N=len(a)foriinrange(int(len(a)/2)):a[i],a[N-i-1]=a[N-i-1],a[i]print(a)上面代码的输出结果是[5,4,6,9]
a=[9,6,4,5]N=len(a)foriinrange(int(len(a)/2)):a[i],a[N-i-1]=a[N-i-1],a[i]print(a)上面代码的输出结果是[5,4,6,9]