下面代码的输出结果是()a=[[1,2,3],[4,5,6],[7,8,9]]s=0forcina:forjinrange(3):s+=c[j]print(s)
给出如下代码MonthandFlower={"1月":"梅花","2月":"杏花","3月":"桃花","4月":"牡丹花",\"5月":"石榴花","6月":"莲花","7月":"玉簪花","8月":"桂花",\"9月":"菊花","10月":"芙蓉花","11月":"山茶花","12月":"水仙花"}n=input("请输入1—12的月份:")print(n+"月份之代表花:"+MonthandFlower.get(str(n)+"月"))以下选项中描述正确的是()
1 Whatwillbedisplayedbythefollowingcode?()m = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]print(m[0][0])
2 Assumem=[[1,2,3],[4,5,6],[7,8,9]],whatarelen(m)?()
3 Assumem=[[1,2,3],[4,5,6],[7,8,9]],whatarelen(m[0])?()
7 Assumex=((1,2),(3,4,5),(5,6,5,9)),whatarelen(x)arelen(x[0])?()
8 Assumex=[[1,2],[3,4,5],[5,6,5,9]],whatarelen(x[0]),len(x[1]),andlen(x[2])?()
12Whatwillbedisplayedbythefollowingcode?()matrix=[[1,2,3,4],[4,5,6,7],[8,9,10,11],[12,13,14,15]]foriinrange(0,4):print(matrix[i][1],end="")
13Whatwillbedisplayedbythefollowingcode?()matrix=[[1,2,3,4],[4,5,6,7],[8,9,10,11],[12,13,14,15]]foriinrange(0,4):print(matrix[1][i],end="")
若有定义:inta[][3]={1,2,3,4,5,6,7,8,9};,则数组a第一维的大小是()
第二维长度为3, 共初始化了9个元素,所以有9/3=3行,故第一维大小为3。
若有定义:inta[]={1,2,3,4,5,6,7,8,9,10};,则值为5的表达式是()
由题可知a[4]的值为5而a[3]的值为4, 所以可以将4用a[3]替换,所以 a[a[3]]的值为5