若有如下定义:inta[3][4]={1,2,3,4,5,6,7,8,9,10,11,12},i;则下列语句的输出结果是()。for(i=0;i<=2;i++)printf(“%d”,a[i][2-i]);
a=[9,6,4,5]N=len(a)foriinrange(int(len(a)/2)):a[i],a[N-i-1]=a[N-i-1],a[i]print(a)上面代码的输出结果是[5,4,6,9]
a=[9,6,4,5]N=len(a)foriinrange(int(len(a)/2)):a[i],a[N-i-1]=a[N-i-1],a[i]print(a)上面代码的输出结果是[5,4,6,9]