$设A={1,2,3,4,5,6,7,8},R是A上的整除关系,B={2,4,6},则集合B的最大元,最小元,上界,下界依次为?$
以下程序段的运行结果为()。intnum[9]={1,2,3,4,5,6,7,8,9},*p;p=num;*(p+1)=0;printf("%d,%d,%d",*p,p[1],(*p)++);A.B.C.D.
下面代码的输出结果是()a=[[1,2,3],[4,5,6],[7,8,9]]s=0forcina:forjinrange(3):s+=c[j]print(s)
1 Whatwillbedisplayedbythefollowingcode?()m = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]print(m[0][0])
2 Assumem=[[1,2,3],[4,5,6],[7,8,9]],whatarelen(m)?()
3 Assumem=[[1,2,3],[4,5,6],[7,8,9]],whatarelen(m[0])?()
12Whatwillbedisplayedbythefollowingcode?()matrix=[[1,2,3,4],[4,5,6,7],[8,9,10,11],[12,13,14,15]]foriinrange(0,4):print(matrix[i][1],end="")
13Whatwillbedisplayedbythefollowingcode?()matrix=[[1,2,3,4],[4,5,6,7],[8,9,10,11],[12,13,14,15]]foriinrange(0,4):print(matrix[1][i],end="")
15 Whatwillbedisplayedbythefollowingcode?()data = [[[1, 2], [3, 4]], [[5, 6], [7, 8]]]print(data[1][0][0])