下面代码的输出结果是()a=[[1,2,3],[4,5,6],[7,8,9]]s=0forcina:forjinrange(3):s+=c[j]print(s)
1 Whatwillbedisplayedbythefollowingcode?()m = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]print(m[0][0])
2 Assumem=[[1,2,3],[4,5,6],[7,8,9]],whatarelen(m)?()
3 Assumem=[[1,2,3],[4,5,6],[7,8,9]],whatarelen(m[0])?()
7 Assumex=((1,2),(3,4,5),(5,6,5,9)),whatarelen(x)arelen(x[0])?()
12Whatwillbedisplayedbythefollowingcode?()matrix=[[1,2,3,4],[4,5,6,7],[8,9,10,11],[12,13,14,15]]foriinrange(0,4):print(matrix[i][1],end="")
13Whatwillbedisplayedbythefollowingcode?()matrix=[[1,2,3,4],[4,5,6,7],[8,9,10,11],[12,13,14,15]]foriinrange(0,4):print(matrix[1][i],end="")
15 Whatwillbedisplayedbythefollowingcode?()data = [[[1, 2], [3, 4]], [[5, 6], [7, 8]]]print(data[1][0][0])
16Whatwillbedisplayedthefollowingcode?()data=[[[1,2],[3,4]],[[5,6],[7,8]]]defttt(m):v=m[0][0]forrowinm:forelementinrow:ifv<element:v=elementreturnvprint(ttt(data[0]))
若有定义:inta[][3]={1,2,3,4,5,6,7,8,9};,则数组a第一维的大小是()
第二维长度为3, 共初始化了9个元素,所以有9/3=3行,故第一维大小为3。
若有定义:inta[]={1,2,3,4,5,6,7,8,9,10};,则值为5的表达式是()
由题可知a[4]的值为5而a[3]的值为4, 所以可以将4用a[3]替换,所以 a[a[3]]的值为5
定义了二维数组inta[3][3]={{1,2},{3,4},{5,6,7}};则数组元素a[2][2]的值是()
数组a的9个值分别为第0行:1 2 0第1行:3 4 0第2行:5 6 7