为你找到 1000 条关于 1-21 的结果
题目:古典问题,有一对兔子,从出生后第3个月起每个月都生一对兔子,小兔子长到第三个月后每个月又生一对兔子,假如兔子都不死,问每个月的兔子总数为多少?需求:一对兔子,从出生后第三个月起每个月都会生出一对兔子,小兔子长到三个月又生一对小兔子。假如兔子不死,问每个月兔子总数。思路:兔子的规律为数列1,1,2,3,5,8,13,21....f1=1f2=2foriinrange(1,21):print('%12d%12d'%(f1,f2))if(i%2)==0:print('')f1=f1+f2______________
25℃,PbI2溶解度为1.21×10-3mol/L,其溶度积为()
(单选题)5.某企业2020年7月1日购入股票100万股,每股21元,其中包含已宣告但尚未发放的股利为每股0.5元,另外支付交易费用10万元,企业将其划分为交易性金融资产。2020年12月31日,股票的公允价值为2200万元,则其账面价值为()万元。
【解析】交易性金融资产采用公允价值计量,所以期末的账面价值就等于公允价值。
2×18年4月1日甲公司以账面价值1400万元、公允价值1500万元的一幢房产换得丁公司持有的乙公司30%的普通股权,达到对乙公司的重大影响能力。投资当日乙公司的账面净资产和可辨认净资产的公允价值均为3500万元。甲公司另行支付相关税费20万元。2×18年4月21日,乙公司宣告分派现金股利200万元,并于5月10日发放。2×18年乙公司实现公允净利润600万元(其中1~3月份公允净利润为200万元)。2×19年4月25日,乙公司宣告分派现金股利300万元,并于5月20日发放红利。2×19年乙公司实现公允净利润500万元。则2×19年末甲公司长期股权投资账面余额为( )万元。
如果原始存款为30万,派生存款为90万,则存款乘数为()。
PARTIIIReadingComprehension(40%)Inthissectionthereare4passagesfollowedby20multiple-choicequestions.Foreachmultiplechoicequestion,therearefoursuggestedanswersmarkedA,B,C,andD.Choosetheoneyouthinkisthebestanswer.PASSAGEONE(1)Attheageoftwelveyears,thehumanbodyisatitsmostvigorous.Ithasyettoreachitsfullsizeandstrength,anditsownerhisorherfullintelligence;butatthisagethelikelihoodofdeathisleast.Earlier,wewereinfantsandyoungchildren,andconsequentlymorevulnerable;later,weshallundergoaprogressivelossofourvigorandresistancewhich,thoughimperceptibleatfirst,willfinallybecomesosteepthatwecanlivenolonger,howeverwellwelookafterourselves,andhoweverwellsociety,andourdoctors,lookafterus.(2)Thisdeclineinvigorwiththepassingoftimeiscalledageing.Itisoneofthemostunpleasantdiscoverieswhichweallmakethatwemustdeclineinthisway,thatifweescapewars,accidentsanddiseaseweshalleventually"dieofoldage",andthatthishappensataratewhichdifferslittlefrompersontoperson,sothatthereareheavyoddsinfavorofourdyingbetweentheagesofsixty-fiveandeighty.Someofuswilldiesooner,afewwilllivelonger—onintoaninthortenthdecade.Butthechancesareagainstit,andthereisavirtuallimitonhowlongwecanhopetoremainalive,howeverluckyandrobustweare.(3)Normalpeopletendtoforgetthisprocessunlessanduntiltheyareremindedofit.Wearesofamiliarwiththefactthatmanages,thatpeoplehaveforyearsassumedthattheprocessoflosingvigorwithtime,ofbecomingmorelikelytodietheolderweget,wassomethingself-evident,likethecoolingofahotkettleorthewearing-outofapairofshoes.Theyhavealsoassumedthatallanimals,andprobablyotherorganismssuchastrees,oreventheuniverseitself,mustinthenatureofthings"wearout".(4)Mostanimalswecommonlyobservedoinfactageaswedo,ifgiventhechancetolivelongenough;andmechanicalsystemslikeawoundwatch,orthesun,doinfactanoutofenergyinaccordancewiththesecondlawofthermodynamics(热力学)(whetherthewholeuniversedoessoisamootpointatpresent).Butthesearenotanalogoustowhathappenswhenmanages.Arun-downwatchisstillawatchandcanberewound.Anoldwatch,bycontrast,becomessowornandunreliablethatiteventuallyisnotworthmending.Butawatchcouldneverrepairitself—itdoesnotconsistoflivingparts,onlyofmetal,whichwearsawaybyfriction.Wecould,atonetime,repairourselves—wellenough,atleast,toovercomeallbutthemostinstantlyfatalillnessesandaccidents.Betweentwelveandeightyyearswegraduallylosethispower;anillnesswhichattwelvewouldknockusover,ateightycanknockusout,andintoourgrave.Ifwecouldstayasvigorousasweareattwelve,itwouldtakeabout700yearsforhalfofustodie,andanother700forthesurvivorstobereducedbyhalfagain.21.WhichofthefollowingstatementsisINCORRECT?
[A]细节推断题。根据各选项内容定位到第1、2段。根据第1段第2句可知,人在长到12岁时身体各个方面包括身材、力量和智力都还有待发展和完 善,所以A(人在12岁发育达到顶峰)的说法不正确,故为本题答案。根据第1段第2句句末的内容可推测。D的...
1.为了提高服务水平,轨道交通的行车间隔在非高峰运营时间的9:00—21:00一般不宜大于10分钟。
21.钱鐘书的著作不包括?
21.下列属于可变更可撤销的合同有()。
Directions:Thereare20incompletesentencesordialoguesinthispart,choosethebestanswertocompletethem.(补全句子,问题或对话)________youhavesaidaboutthisisveryinteresting.
Directions:Thereare20incompletesentencesordialoguesinthispart,choosethebestanswertocompletethem.(补全句子,问题或对话)21.________youhavesaidaboutthisisveryinteresting.
Directions:Thereare20incompletesentencesordialoguesinthispart,choosethebestanswertocompletethem.(补全句子,问题或对话)21.Thewholeclassisin_______discussion.
以下程序的输出结果是ls1=[1,2,3,4,5]ls2=[3,4,5,6,7,8]cha1=[]foriinls2:ifinotinls1:cha1.append(i)print(cha1)
以下代码的输出结果是foriinrange(1,6):ifi%4==0:breakelse:print(i,end=’,’)
用某种排序方法对关键字序列(25,84,21,47,15,27,68,35,20)进行排序时,序列的变化情况如下:第1趟:20,15,21,25,47,27,68,35,84第2趟:15,20,21,25,35,27,47,68,84第3趟:15,20,21,25,27,35,47,68,84则所采用的排序方法是()
D