a=[9,6,4,5]N=len(a)foriinrange(int(len(a)/2)):a[i],a[N-i-1]=a[N-i-1],a[i]print(a)上面代码的输出结果是[5,4,6,9]
下列程序的输出结果是()。#includestructabc{inta,b,c;};main(){structabcs[2]={{1,2,3},{4,5,6}};intt;t=s[0].a+s[1].b%s[0].c;printf("%d\n",t);}