为你找到 1000 条关于 土木1-4 的结果
Engineeringstudentsaresupposedtobeexamplesofpracticality(实用性)andrationality(理性),butwhenitcomestomycollegeeducationIamanidealistandafool.InhighschoolIwantedtobeanelectricalengineerand,ofcourse,anysensiblestudentwithmyaimswouldhavechosenacollegewithalargeengineeringdepartment,famousreputationandlotsofgoodlabsandresearchequipment.Butthat’snotwhatIdid.Ichosetostudyengineeringatasmallliberal-arts(文科)universitythatdoesn’tevenofferamajorinelectricalengineering.Obviously,thiswasnotapracticalchoice;Icamehereformorenoblereasons.Iwantedabroadeducationthatwouldprovidemewithflexibilityandavaluesystemtoguidemeinmycareer.Iwantedtoopenmyeyesandexpandmyvisionbyinteractingwithpeoplewhoweren’tstudyingscienceorengineering.Myparents,teachersandotheradultspraisedmeforsuchawisechoice.TheytoldmeIwaswiseandmaturebeyondmy18years,andIbelievedthem.IheadedofftothecollegeandsureIwasgoingtohaveanadvantageoverthosestudentswhowenttobigengineering"factories"wheretheydidn’tcareifyouhadvaluesorwereflexible.Iwasgoingtobeacompleteengineer:technicalgeniusandsensitivehumanistallinone.NowI’mnotsosure.Somewherealongthewaymynobleideascrashedintoreality,asallnobleideasfinallydo.Afterthreeyearsofstrugglingtobalancemath,physicsandengineeringcourseswithliberal-artscourses,Ihavelearnedtherearereasonswhyfewengineeringstudentstrytoreconcileengineeringwithliberal-artscoursesincollege.Therealitythathasblockedmypathtobecomethetypicalsuccessfulstudentisthatengineeringandtheliberalartssimplydon’tmixaseasilyasIsupposedinhighschool.Individuallytheyshapeapersoninverydifferentways;togethertheythreatentoconfuse.Thestruggletoreconcilethetwofieldsofstudyisdifficult.4.Theunderlinedsentenceinthe1stparagraphmeans___________.
当消费函数为c=a+by,(a>0,0<b<1),这表明,平均消费倾向
4、保险合同中,基本条款的效力优于附加条款。()
三、判断题(每小题1分,共10分)1、与人的疏忽或过失相关的风险因素称为道德风险因素()
4、经营商业性保险业务的主体不包括()。
二、单项选择(每小题1分,共15分)1、在下面的风险因素中,属于心理风险因素的是:()。
二、单项选择(每小题1分,共15分)1、消费者偏好转移,会引起旧产品失去销路,增加对新产品的需求,这属于()。
三、判断题(每小题1分,共10分)1、人寿保险采用均衡保险费,即保险人在各年度均收取数额相等的保险费把被保险人应若干年负担的保险费的总和,运用科学的计算方法平均分摊于各个年度。()
建设单位领取施工许可证后因故4个月未能开工,又未申请延期,该施工许可证()。
10.inta[10]={0,1,2,3,4,5,6,7,8,9},*p=a;则p+5相当于a[5]。
1.inta[3][4]={{1},{5},{9}};它的作用是将数组各行第一列的元素赋初值,其余元素值为0.
10.inta[10]={0,1,2,3,4,5,6,7,8,9},*p=a;则p+5相当于a[5].
1.inta[3][4]={{1},{5},{9}};它的作用是将数组各行第一列的元素赋初值,其余元素值为0.
1.Whenyouhavefinishedwiththatbook,don’tforgettoputitbackontheshelf,____?
4.Whichoftheitalicizedpartsexpressesafuturetense?