7、从独立性来看，社会审计()。

以下程序中，请选出错误的那行process(clk，d)BeginSignald:std_logic;----------1Variableq:std_logic;----------2Ifclk`eventandclk=’1’Thenq<=d;----------3endif;----------4Endprocess；

Directions:Thereare3passagesinthissection.Eachpassageisfollowedby5questionsorunfinishedstatements.ForeachofthemtherearefourchoicesmarkedA),B),C)andD).YoushoulddecideonthebestchoiceandmarkthecorrespondingletterontheAnswerSheet.Text1Engineeringstudentsaresupposedtobeexamplesofpracticality(实用性)andrationality(理性),butwhenitcomestomycollegeeducationIamanidealistandafool.InhighschoolIwantedtobeanelectricalengineerand,ofcourse,anysensiblestudentwithmyaimswouldhavechosenacollegewithalargeengineeringdepartment,famousreputationandlotsofgoodlabsandresearchequipment.Butthat’snotwhatIdid.Ichosetostudyengineeringatasmallliberal-arts(文科)universitythatdoesn’tevenofferamajorinelectricalengineering.Obviously,thiswasnotapracticalchoice;Icamehereformorenoblereasons.Iwantedabroadeducationthatwouldprovidemewithflexibilityandavaluesystemtoguidemeinmycareer.Iwantedtoopenmyeyesandexpandmyvisionbyinteractingwithpeoplewhoweren’tstudyingscienceorengineering.Myparents,teachersandotheradultspraisedmeforsuchawisechoice.TheytoldmeIwaswiseandmaturebeyondmy18years,andIbelievedthem.IheadedofftothecollegeandsureIwasgoingtohaveanadvantageoverthosestudentswhowenttobigengineering"factories"wheretheydidn’tcareifyouhadvaluesorwereflexible.Iwasgoingtobeacompleteengineer:technicalgeniusandsensitivehumanistallinone.NowI’mnotsosure.Somewherealongthewaymynobleideascrashedintoreality,asallnobleideasfinallydo.Afterthreeyearsofstrugglingtobalancemath,physicsandengineeringcourseswithliberal-artscourses,Ihavelearnedtherearereasonswhyfewengineeringstudentstrytoreconcileengineeringwithliberal-artscoursesincollege.Therealitythathasblockedmypathtobecomethetypicalsuccessfulstudentisthatengineeringandtheliberalartssimplydon’tmixaseasilyasIsupposedinhighschool.Individuallytheyshapeapersoninverydifferentways;togethertheythreatentoconfuse.Thestruggletoreconcilethetwofieldsofstudyisdifficult.1.Whydidtheauthorchoosetostudyengineeringatasmallliberal-artsuniversity?

Itiseasiertonegotiateinitialsalaryrequirementbecauseonceyouareinside,theorganizationalconstraints(约束)influencewageincreases.Onething,however,iscertain:yourchancesofgettingtheraiseyoufeelyoudeservearelessifyoudon’tatleastaskforit.Mentendtoaskformore,andtheygetmore,andthisholdstruewithotherresources,notjustpayincreases.ConsiderBeth’sstory:IdidnotgetwhatIwantedwhenIdidnotaskforit.Wehadcubicle(小隔间)officesandwindowoffices.Isatinthecubicleswithseveralmalecolleagues.Onebyonetheyweremovedintowindowoffices,whileIremainedinthecubicles,severalmaleswhowerehiredaftermealsowenttooffices.Oneinparticulartoldmehewasnextinlineforanofficeandthatithadbeenpartofhisnegotiationsforthejob.IguesstheythoughtmecontenttostayinthecubiclessinceIdidnotvoicemyopinioneitherway.Itwouldbeniceifweallreceivedautomaticpayincreasesequaltoourmerit,but“nice”isn’taqualityattributedtomostorganizations.Ifyoufeelyoudeserveasignificantraiseinpay,you’llprobablyhavetoaskforit.Performanceisyourbestbargainingchip(筹码)whenyouareseekingaraise.Youmustbeabletodemonstratethatyoudeservearaise.Timingisalsoagoodbargainingchip.Ifyoucangiveyourbosssomethingheorsheneeds(anewclientorasizablecontract,forexample)justbeforemeritpaydecisionsarebeingmade,youaremorelikelytogettheraiseyouwant.Useinformationasabargainingchiptoo.Findoutwhatyouareworthontheopenmarket.Whatwillsomeoneelsepayforyourservices?Gointothenegotiationspreparedtoplaceyourchipsonthetableattheappropriatetimeandpreparedtousecommunicationstyletoguidethedirectionoftheinteraction.7.WhatcanbeinferredfromBeth’sstory?

当消费函数为c=a+by，（a>0，0<b<1），这表明，平均消费倾向

7、受益人由投保人在投保时指定，并在保险期间内可随意变更受益人。（）

三、判断题（每小题1分，共10分）1、与人的疏忽或过失相关的风险因素称为道德风险因素（）

7、依法成立的保险合同条款对合同当事人产生的约束力的情况属于（）。

二、单项选择（每小题1分，共15分）1、在下面的风险因素中，属于心理风险因素的是：（）。

二、单项选择（每小题1分，共15分）1、消费者偏好转移，会引起旧产品失去销路，增加对新产品的需求，这属于（）。

三、判断题（每小题1分，共10分）1、人寿保险采用均衡保险费，即保险人在各年度均收取数额相等的保险费把被保险人应若干年负担的保险费的总和，运用科学的计算方法平均分摊于各个年度。（）

40.若有数组定义intm[][2]={1,3,5,7,9}，则以下叙述正确的是

18.有程序如下：#include<stdio.h>structcmplx{intx;inty;}cnum[2]={1,3,2,7};intmain(){printf("%d\n",cnum[0].y/cnum[0].x*cnum[1].x);return0;}该程序执行后输出的结果是

10.inta[10]={0,1,2,3,4,5,6,7,8,9},*p=a;则p+5相当于a[5]。

18．有程序如下：#include<stdio.h>structcmplx{intx;inty;}cnum[2]={1,3,2,7};intmain(){printf("%d\n",cnum[0].y/cnum[0].x*cnum[1].x);return0;}该程序执行后输出的结果是