若向量组$alpha_{1},alpha_{2},alpha_{3},alpha_{4}$线性无关,则向量组$alpha_{1}-alpha_{2},alpha_{2}-alpha_{3},alpha_{3}-alpha_{4},alpha_{4}-alpha_{1}$也线性无关.
因为$(alpha_{1}-alpha_{2})+(alpha_{2}-alpha_{3})+(alpha_{3}-alpha_{4})+(alpha_{4}-alpha_{1})=0$,所以$alpha_{1}-alpha_{2},alp...
物理页帧数量为4,虚拟页访问序列为0,3,2,0,1,3,4,3,1,0,3,2,1,3,4,请问采用CLOCK置换算法(用1个bit表示存在时间)的缺页次数为()
9
9Whatwillbedisplayedbythefollowingprogram?()values=[[3,4,5,1],[33,6,1,2]]v=values[0][0]forrowinrange(0,len(values)):forcolumninrange(0,len(values[row])):ifv<values[row][column]:v=values[row][column]print(v)
10Whatwillbedisplayedbythefollowingprogram?()values=[[3,4,5,1],[33,6,1,2]]v=values[0][0]forlstinvalues:forelementinlst:ifv>element:v=elementprint(v)
11Whatwillbedisplayedbythefollowingprogram?()values=[[3,4,5,1],[33,6,1,2]]forrowinvalues:row.sort()forelementinrow:print(element,end="")print()
12Whatwillbedisplayedbythefollowingcode?()matrix=[[1,2,3,4],[4,5,6,7],[8,9,10,11],[12,13,14,15]]foriinrange(0,4):print(matrix[i][1],end="")
13Whatwillbedisplayedbythefollowingcode?()matrix=[[1,2,3,4],[4,5,6,7],[8,9,10,11],[12,13,14,15]]foriinrange(0,4):print(matrix[1][i],end="")