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Considerthefollowingabruptjunctiondiode(m=0.5):Cj0=3x10^-3(F/(m^2)),AD=1μm^2,andФ0=0.64V.Ifweapplyareversebiasof-2.5V,what’sthevalueofthetotaljunctioncapacitance?(selectthenearestvalue)

题型：单选题

选项

A. A.)t1fF

B. B.)t1.15fF

C. C.)t1.35fF

D. D.)t1.5fF

正确答案：C

名词解析

Solution: c)Cj=ADCj0(1-VD/Ф0)^(-0.5)=1x10^(-12)x3x10^(-3)x(1+2.5/0.64)^(-0.5)=1.35fF